Ответ:

1.

a) √484 = 22

b) (-19)2 = 361

c) -(√19)² = -19

d) √1960000 = 1400

2.

a) 3√2500 – 0,5√1600 + √225 = 3 * 50 - 0,5 * 40 + 15 = 145

b) 2 + F1z = undefined (because F1z is not specified)

c) √30 * 120 = 120√30

d) √112 = 4√7

3.

a) 5√1,4 = √(25*1,4) = √35

b) 26√13 = √(676*13) = 26√13

c) B+√11 = B+√11 (cannot be simplified further)

d) 2-11√ = 2-11√ (cannot be simplified further)

e) 2,90√0,01 +√729 = 2,9 * 0,1 + 27 = 27,9

4.

a) √1200 = √(4*300) = 20√3

b) 243 = 3³

5.

a) To simplify the denominator of √(43/x), we can rationalize it by multiplying both the numerator and denominator by √x. This gives us: √(43x)/x.

b) To simplify √67-√74, we cannot simplify it further as both terms are already in their simplest forms.

c) To simplify -1 + 15/45, we can first simplify 15/45 to 1/3, and then add it to -1 to get -2/3.

6.

a) √a(a+3)-a-3√a = √a * √(a+3) - a - √a * √3 = √a * √(a+3) - a√3 - a

b) (√2-√18) * √2 = √2 * √2 - √2 * √18 = 2 - 6√2

c) (3-√5) +6√5 = 3√5 + 3

7.

a) We can simplify √7+√35 by factoring out √7: √7(1+5) / (1+5) = √7.

b) √490 = √(49*10) = 7√10

c) √10/2 = √5/√2 * √2/√2 = √10/2

d) (2₂-6) * (√x-1)(√x+1)+1-x = -4(√x²-1)+1-x = -4√x²+4-x

Объяснение:

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